Gambar 1 nomer 1 a,b,c dan d Gambar 2 nomer 2,3,4 dan 5 Gambar 3 dan gambar 4 dan gambar 5 =√ nomer .... Question from @chikajessicaa

October 2018 1 81 Report

Gambar 1 nomer 1 a,b,c dan d
Gambar 2 nomer 2,3,4 dan 5
Gambar 3 dan gambar 4 dan gambar 5 =√ nomer 1-10
Help me please

ImmanuelSinaga Gambar pertama :

$1a)~~~4^5~=~1024 \\ ~~~~~~~^4log~1024~=~5 \\\\ 1b)~~~10^{-4}~=~\frac{1}{10.000} \\ ~~~~~^{10}log~\frac{1}{10.000}~=~-4 \\ \\ 1c)~~~3^0~=~1 \\ ~~~~~~^3log~1~=~0 \\ \\ 1d)~~~3^{-\frac{3}{4}}~=~\frac{1}{\sqrt[4]{27}} \\ ~~~~~~~^3log~\frac{1}{\sqrt[4]{27}}~=~-\frac{3}{4} \\\\\boxed{\bold{bentuk~umum}~~:~~a^c~=~b~===\ \textgreater \ ~~^alog~b~=~c}$

Gambar kedua :
$\boxed{\bold{bentuk~umum~~:~~^alog~b~=~c~===\ \textgreater \ ~~~a^c~=~b}} \\ \\a)~~~log~1~=~^{10}log~1~=~0 \\ ~~~~~~10^{0}~=~1 \\ b)~~~^3log~\frac{1}{3}~=~-1 \\ ~~~~~~3^{-1}~=~\frac{1}{3} \\ c)~~~^3log~81~=~4 \\ ~~~~~~~3^4~=~81 \\ d)~~~^3log~\frac{1}{3\sqrt{3}}~=~-\frac{3}{2} \\ ~~~~~~~3^{-\frac{3}{2}}~=~\frac{1}{3\sqrt{3} }$
$3a)~~~^2log~32~+~^2log~8~-~^2log~2~=~^2log~2^5~+~^2log~2^3~-~1 \\ ~~~~~~~=5~+~3~-~1 \\ ~~~~~~~=7 \\ 3b)~~~\frac{log^26-log^23}{log~2} ~=~\frac{(log~6~-~log~3)(log~6~+~log~3)}{log~2}~=~\frac{log~(\frac{6}{3})~\times~log~(6~\times~3)}{log~2} \\ ~~~~~~~=\frac{log~2~\times~log~12}{log~2}~=~log~12$
$$\begin{align} ^{18}log~50~~&=~~\frac{^3log~50}{^3log~18} \\ &=~\frac{^3log~(2\times5^2)}{^3log~(2~\times~3^2)} \\ &=\frac{~^3log~2~+~^3log~5^2}{^3log~2~+~^3log~3^2}~=~\frac{\frac{1}{^2log~3}+2.^3log~5}{\frac{1}{^2log~3}+2.^3log~3} \\ &=~\frac{\frac{1}{p}+2q}{\frac{1}{p}+2} ~=~\frac{\frac{1+2pq}{p}}{\frac{1+2p}{p}} \\ &=~\frac{1+2pq}{1+2p} \end{align}$ $$\begin{align} ^alog~81~-~2~^alog~27+^alog~27+^alog~243~&=~6 \\ ^alog~81~-~~^alog~27+^alog~243~&=~6 \\ ^alog~(\frac{81}{27}\times~243)~&=~6 \\ ^alog~729~&=~6 \\ ^alog~3^{6}~&=~6 \\ \bold{Maka~a~&=~3}\end{align}$

Gambar tiga :
$\displaystyle 1)~~~\left[\frac{1}{m^2}\right]^4~=~m^p \\ \\ ~~~~~~~~~[m^{-2}]^4~=~m^p \\ \\ ~~~~~~~m^{(-2~\times~4)}=m^{-8}~=~m^p \\ ~~~~~~~~~~~~~~~~~~p~=~-8 \\ \\ 2)~~~\frac{\sqrt{2}}{\sqrt{6}+\sqrt{3}}~\times~\frac{\sqrt{6}-\sqrt{3}}{\sqrt{6}-\sqrt{3}}~=~\frac{\sqrt{2\times6}-\sqrt{2\times3}}{(\sqrt{6})^2-(\sqrt{3})^2}~=~\frac{\sqrt{12}-\sqrt{6}}{6-3} \\ \\ ~~~~~~~~=~\frac{1}{3}(2\sqrt{3}-\sqrt{6}) \\ \\ 3)~~~\left[\frac{3}{2a}\right]^{-2}~=~\left[\frac{2a}{3}\right]^2~=~\frac{4a^2}{9}$

Gambar empat :
$\displaystyle 4)~~~\sqrt{\frac{18a^3}{b^4}}~=~\sqrt{\frac{2~\times~3^2~\times~a~\times~a^2}{(b^2)^2}}~=~\frac{3a\sqrt{2a}}{b^2} \\\\ 5)~~~^6log~4~\times~^2log~36~~\times~^4log~6\\ \\ ~~~~~~=^6log~2^2~\times~^2log~6^2 ~\times~^2^{^2}log~6 \\ ~~~~~~=~2~\times~2~\times~\frac{1}{2}~\times~^6log~\not2~\times~^{\not2}log~6~\times~^2log~6 \\ ~~~~~~=~2~\times~^2log~6~=~2b$ $6)~~~\displaystyle \frac{2^9~\times~2^6}{2^5}~=~2^{9+6-5}~=~2^{10}~=~1024$

Gambar kelima :
$\displaystyle 8)~~~\boxed{tak~dapat~diketahui,~option~a.} \\ \\ 9)~~~~maaf~kurang~jelas \\ \\10)~~~\frac{3a^{-2}b^2}{a^3~b^3}~=~\frac{3b^2}{a^3~a^2~b^3}~=~\frac{3b^2}{a^5~b^3}~=~\frac{3}{a^5~b}~=~\frac{3}{(2)^5~\times~5}~=~\frac{3}{160}$

3 votes Thanks 3

chikajessicaa tmakasih kasih bgt ka :D

ImmanuelSinaga sama-sama :)

chikajessicaa Nomer 9 (3x pangkat 0.. y pangkat 6.. Z pangkat 2) pangkat 4

chikajessicaa Tolong jwb nomer 9 ya kak :)

ImmanuelSinaga iya , tapi nggk jelas dek ^_^

chikajessicaa Nnti sya krim lagi ya ka gambar nya

ImmanuelSinaga oke :D

ImmanuelSinaga ( 3x^{0} . y^{6} . z^{2} )^4 3^{4} . y^{6.4} . z^{2.4} 81 . y^{24} . z^{8} 81y^{24}z^{8}

ImmanuelSinaga udah yah

chikajessicaa Udh ka trima kasih ^•^