Question

F(x)=x2-2x+3 jika domain {0,1,2,3} adalah

Answer 1

F(x) = x²-2x+3
f(0) = 0²-2.0+3 =3
f(1) = 1²-2.1+3 = 1-2+3 = 2
f(2) = 2²-2.2+3 = 4-4+3 = 3
f(3) = 3²-2.3+3 = 9-6+3 = 6

Answer 2

F(x) = x²-2x+3
f(0) = 0²-2(0)+3 = 3
f(1) = 1²-2(1)+3 = 2
f(2) = 2²-2(2)+3 = 3
f(3) = 3²-2(3)+3 = 6
daerah hasilnya: {2,3,6}