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f(3) = 3a + b = -1
-1a = 2 >>(dikurang)
a = 2 ÷ -1
a = -2
2a + b = 1
2(-2) + b = 1
-4 + b = 1
b= 1+4
b= 5 ...
f(3) = 3a + b = -1
3a + b = -1
3a + 1 - 2a= -1
a = -2
subs a=-2 ke
b = 1 - 2 a
b = 1 - 2(-2)
b = 1+4
b = 5
jadi, a =-2 dan b = 5