FUNKCJE WYMIERNE
rozwiąż równania :
a)
6x≠0
x≠0
D: x∈R -{0}
2x+5 =6x·x
6x²-2x-5=0
Δ=(-2)²-4·6·(-5) = 4+120=124
√Δ=2√31
x₁= (2+2√31) /12 =( 1+√31)/6
x₂==(2-2√31)/12 = (1-√31)/6
b)
x²≠0
-4x+20=0
-4x=-20
x=5
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a)
6x≠0
x≠0
D: x∈R -{0}
2x+5 =6x·x
6x²-2x-5=0
Δ=(-2)²-4·6·(-5) = 4+120=124
√Δ=2√31
x₁= (2+2√31) /12 =( 1+√31)/6
x₂==(2-2√31)/12 = (1-√31)/6
b)
x²≠0
x≠0
D: x∈R -{0}
-4x+20=0
-4x=-20
x=5