January 2019 1 19 Report
Funkcje trygonometryczne. Rozwiąż równania:

1. cos 3x = - \frac{ \sqrt{3} }{2}

gdzie x nalezy do przedziału <- \frac{ \pi }{2} , \pi >

2. 2 cos^{2}2x + 3cos 2x - 2 = 0

3.  cos^{2}x + \sqrt{2} sin x - 1,5 = 0
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