January 2019 1 21 Report
Funkcje trygonometryczne. Rozwiąż równania:

1. cos 3x = - \frac{ \sqrt{3} }{2}

gdzie x nalezy do przedziału <- \frac{ \pi }{2} , \pi >

2. 2 cos^{2}2x + 3cos 2x - 2 = 0

3.  cos^{2}x + \sqrt{2} sin x - 1,5 = 0
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.