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f(x) = (m - 1)x -2
f(x) = ax + b
a > 0, funkcja rosnąca
m - 1 > 0
m > 1
8.
f(x) = (m + √3)x - √3, jest malejaca, gdy:
a < 0
m + √3 < 0
m < -√3
{a = 0
{b = 2
10.
y = 3
y = 2x + 4
3 = 2x + 4
2x = 3 - 4
2x = -1 /:2
x = - 1/2
P =(-1/2; 3)
11.
y = ax + b - rownanie kierunkowe prostej
-6a + b = 7
6a + b = 1
----------------- +
2b = 8 /:2
b = 4
6a = 1 - 4
6a = -3 /:6
a = -1/2