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Wykonaj dodawanie. Odpowiedź podaj w najprostszej postaci.

\frac{3}{x} + \frac{6}{x - 2} =


\frac{1}{x - 1} + \frac{1}{x +3} =


\frac{x - 2}{x - 1} + \frac{x - 3}{1 - x} =


\frac{4}{x +3} + \frac{1 - 4x}{x^{2} + 3x} =

Wykonaj działania:
\frac{3}{x +4} + \frac{5}{x - 4}=


\frac{6}{x - 3} - \frac{4}{3 - x}=

\frac{x}{x^{2} - 1} - \frac{x + 1}{x - 1y} =

 \frac{x + 3}{x^{2} + 2x} + \frac{1}{2x +4} =

\frac{xx - 1}{x^{2} + 3x} + \frac{x + 2}{x^{2} - 4x} =

 \frac{x + 1}{x^{2} +2x +1} - \frac{x}{x^{2} +x}=


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