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f(x+1)-f(x)=3
a(x+1)+b-(ax+b)=ax+a+b-ax-b=a
a=3
lub od razu można napisać, że a=3 bo f(x+1)-f(x)=tga=a
y=3x+b
Podstawiamy punkt (2,4)
4=3*2+b
4=6+b
b=-2
y=3x-2