Odpowiedź:
f(x ) = 3 x² + 3 x - 6
a = 3 b = 3 c = - 6
więc
p =
Δ = b² - 4 a*c = 3² - 4*3*( -6) = 9 + 72 = 81
q =
f(x) = a*( x - p)² + q - postać kanoniczna
f(x ) = 3*( x - (- ))² + ( - 6 )
Odp. f(x ) = 3*( x +
============================
II sposób:
p = -
q = f ( p ) = f ( -
f(x) = 3*( x +
-----------------------------------
Szczegółowe wyjaśnienie:
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Odpowiedź:
f(x ) = 3 x² + 3 x - 6
a = 3 b = 3 c = - 6
więc
p =
Δ = b² - 4 a*c = 3² - 4*3*( -6) = 9 + 72 = 81
q =
f(x) = a*( x - p)² + q - postać kanoniczna
więc
f(x ) = 3*( x - (- ))² + ( - 6 )
Odp. f(x ) = 3*( x +
============================
II sposób:
p = -
q = f ( p ) = f ( -
f(x) = 3*( x +
-----------------------------------
Szczegółowe wyjaśnienie: