Karena f(x) ≤ 0 dan f(a) = 0 ada, maka f(x) memiliki akar kembar.
Karena f(1) = 0, artinya 1 merupakan akar dari f(x), sehingga :
f(x) = a(x - 1)²
f(-1) + 1 = 0
a(-1 - 1)² + 1 = 0
a(-2)² + 1 = 0
4a + 1 = 0
4a = -1
a = -1/4
Maka, f(x) = (-1/4)(x - 1)²
f(-3) + f(5) = (-1/4)(-3 - 1)² + (-1/4)(5 - 1)²
= (-1/4)((-4)² + 4²)
= (-1/4)(16 + 16)
= (-1/4)(32)
= -8
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Verified answer
Karena f(x) ≤ 0 dan f(a) = 0 ada, maka f(x) memiliki akar kembar.
Karena f(1) = 0, artinya 1 merupakan akar dari f(x), sehingga :
f(x) = a(x - 1)²
f(-1) + 1 = 0
a(-1 - 1)² + 1 = 0
a(-2)² + 1 = 0
4a + 1 = 0
4a = -1
a = -1/4
Maka, f(x) = (-1/4)(x - 1)²
f(-3) + f(5) = (-1/4)(-3 - 1)² + (-1/4)(5 - 1)²
= (-1/4)((-4)² + 4²)
= (-1/4)(16 + 16)
= (-1/4)(32)
= -8