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f=-2a+b=-13 ..…(1)
f(5)=a.(5)+b=22
f= 5a+b=22...(2)
eliminasi b
-2a+b=-13
5a+b=22
---------- -
-7a=-35
a=-35
----
-7
a=5
substitusi a=5 ke pers 1
-2a+b=-13
-2(5)+b=-13
-10+b=-13
b=-13+10
b=-3
b. rumus = f(x)=5x-3