f(x)=ax+8
A.f(3)=a(3) + 8=-4
=3a + 8=-4
=3a=-12
a=-12 : 3
a=-4
B.f(x)=-4x + 8
C.f(5)=-4(5) + 8
=-20 + 8
=-12
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f(x)=ax+8
A.f(3)=a(3) + 8=-4
=3a + 8=-4
=3a=-12
a=-12 : 3
a=-4
B.f(x)=-4x + 8
C.f(5)=-4(5) + 8
=-20 + 8
=-12
#Makasih :)
f(x) = ax + 8
f(-3) = a(-3) + 8
-4 = -3a + 8
-4 - 8 = -3a
-12 = -3a
3a = 12
a = 12/3
a = 4
soal b
f(x) = ax + 8
f(x) = 4x + 8
soal c
f(x) = 4x + 8
f(5) = 4(5) + 8
f(5) = 20 + 8
f(5) = 28