\frac{ \sqrt[3]{4 ^{5-x} } }{8} = \frac{1}{ 2^{2x+1} } nilai x adalah....
Takamori37
![\displaystyle \frac{ \sqrt[3]{4 ^{5-x} } }{8} = \frac{1}{ 2^{2x+1} } \\ \frac{4^{\frac{5-x}{3}}}{8}=2^{-(2x+1)} \\ 8^{-1}.2^{\frac{10-2x}{3}}=2^{-2x-1} \\ 2^{-3}.2^{\frac{10-2x}{3}}=2^{-2x-1} \\ 2^{\frac{10-2x}{3}-3}}=2^{-2x-1} \\ 2^{\frac{1-2x}{3}}}=2^{-2x-1} \\ \frac{1-2x}{3}=-2x-1 \\ 1-2x=-6x-3 \\ 4x=-4 \\ x=-1](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cfrac%7B+%5Csqrt%5B3%5D%7B4+%5E%7B5-x%7D+%7D+%7D%7B8%7D+%3D+%5Cfrac%7B1%7D%7B+2%5E%7B2x%2B1%7D+%7D+%5C%5C+%5Cfrac%7B4%5E%7B%5Cfrac%7B5-x%7D%7B3%7D%7D%7D%7B8%7D%3D2%5E%7B-%282x%2B1%29%7D+%5C%5C+8%5E%7B-1%7D.2%5E%7B%5Cfrac%7B10-2x%7D%7B3%7D%7D%3D2%5E%7B-2x-1%7D+%5C%5C+2%5E%7B-3%7D.2%5E%7B%5Cfrac%7B10-2x%7D%7B3%7D%7D%3D2%5E%7B-2x-1%7D+%5C%5C++2%5E%7B%5Cfrac%7B10-2x%7D%7B3%7D-3%7D%7D%3D2%5E%7B-2x-1%7D+%5C%5C+2%5E%7B%5Cfrac%7B1-2x%7D%7B3%7D%7D%7D%3D2%5E%7B-2x-1%7D+%5C%5C+%5Cfrac%7B1-2x%7D%7B3%7D%3D-2x-1+%5C%5C+1-2x%3D-6x-3+%5C%5C+4x%3D-4+%5C%5C+x%3D-1 "\displaystyle \frac{ \sqrt[3]{4 ^{5-x} } }{8} = \frac{1}{ 2^{2x+1} } \\ \frac{4^{\frac{5-x}{3}}}{8}=2^{-(2x+1)} \\ 8^{-1}.2^{\frac{10-2x}{3}}=2^{-2x-1} \\ 2^{-3}.2^{\frac{10-2x}{3}}=2^{-2x-1} \\ 2^{\frac{10-2x}{3}-3}}=2^{-2x-1} \\ 2^{\frac{1-2x}{3}}}=2^{-2x-1} \\ \frac{1-2x}{3}=-2x-1 \\ 1-2x=-6x-3 \\ 4x=-4 \\ x=-1")
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