Fog(x) = gof(x) maka nilai a=... jika diketahui f(x)=2-x dan g(x) = 2x+a+1
inoid
![$\begin{align}f\circ g(x)&=g\circ f(x)\\[4pt]f\left(g(x)\right)&=g\left(f(x)\right)\\[4pt]f(2x+a+1)&=g(2-x)\\[4pt]2-(2x+a+1)&=2(2-x)+a+1\\[4pt]2-2x-a-1&=4-2x+a+1\\[4pt]-2x-a+1&=-2x+a+5\\[4pt]2a&=-4\\[4pt]a&=-2\end{align}](https://tex.z-dn.net/?f=%24%5Cbegin%7Balign%7Df%5Ccirc+g%28x%29%26%3Dg%5Ccirc+f%28x%29%5C%5C%5B4pt%5Df%5Cleft%28g%28x%29%5Cright%29%26%3Dg%5Cleft%28f%28x%29%5Cright%29%5C%5C%5B4pt%5Df%282x%2Ba%2B1%29%26%3Dg%282-x%29%5C%5C%5B4pt%5D2-%282x%2Ba%2B1%29%26%3D2%282-x%29%2Ba%2B1%5C%5C%5B4pt%5D2-2x-a-1%26%3D4-2x%2Ba%2B1%5C%5C%5B4pt%5D-2x-a%2B1%26%3D-2x%2Ba%2B5%5C%5C%5B4pt%5D2a%26%3D-4%5C%5C%5B4pt%5Da%26%3D-2%5Cend%7Balign%7D "$\begin{align}f\circ g(x)&=g\circ f(x)\\[4pt]f\left(g(x)\right)&=g\left(f(x)\right)\\[4pt]f(2x+a+1)&=g(2-x)\\[4pt]2-(2x+a+1)&=2(2-x)+a+1\\[4pt]2-2x-a-1&=4-2x+a+1\\[4pt]-2x-a+1&=-2x+a+5\\[4pt]2a&=-4\\[4pt]a&=-2\end{align}")
1 votes
Thanks 1
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.