Question

Find the coordinates of the point A' which is the symmetric point of A(3,2) with respect to the line 2x + y - 12 =0

tolong donggg

Answer 1

2x+y-12=0
-y=2x-12
m¹=-2. m¹xm²=-1
-2xm²=-1
m²=-1/-2
m²=1/2
y-y¹=m(x-x¹)
y-2=1/2(x-3)
y=1/2x-3/2+2
2y-x=3.5