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altura : √3 × L/2
Area = √3 / 4 × L^2
x2=h2+(x/2)¨2
x2=h2+x2/4
x2-x2/4=h2
(4x2-x2)/4=h2
3x2/4= h2
h=raiz(3x2/4)
h = (raiz(3)/2)*x................Ahora aplicamos la formula del area del triangulo A=bh/2 y queda
A=(raiz(3)/2)*x*x/2
A= (raiz(3)/4)*x