Energia kinetyczna walca o masie m=50dkg toczacego sie bez poslizgu wynosi 24J. jaka jest predkosc srodka masy walca? (moment bezwladnosci walca: I=½ mr²)
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Ek=24J
m=50dkg=0,5kg
Ek=mV²/2/*2
V=?
2Ek=mV²/:m
2Ek/m=V²
V=√2Ek/m
V=√24J:0,5kg
V=√48m/s