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R = x
Q = x + 15
P = (x + 15)/2
_____________ , ahora sumando
R + Q + P = x + x + 15 + (x + 15)/2
Pero la suma de los ángulos internos de un triángulo: P + Q + R = 180
180 = x + x + 15 + (x + 15)/2
multiplicamos por 2 a ambos miembros de la ecuación
2.180 = 2x + 2x + 30 + x + 15
360 = 5x + 45
5x = 315 => x = 63
P = (63+15)/2 = 39º
Q = 63 +15 = 78º
R = 63º