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60=(3x10)+(2x15)
10 triciclos y 15 bicicletas
Y=triciclo
5+Y=X
2X+3Y=60
2X+3Y=60
2(5+Y)+3Y=60
10+2Y+3Y=60
2Y+3Y=50
5Y=50
Y=10
Y+5=X
10+5=X
X=15
Rta: Hay 15 bicicletas y 10 triciclos