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Katoda= Cu2+ + 2e -> Cu
Anoda= Sn -> Sn2+ + 2e
b) E° Sel= 0,34-(-0,14) = 0,48 V
c) K pada 25°C
E° = (0,02569÷n) × lnK
0,48 = (0,02569÷2)×lnK
lnK = 37,36
K = e^37,36 = 1,679×10^16.
:)