x²+3x-88=0
(x-8)(x+11)
x=8 x=-11
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x²+3x-88=0
(x-8)(x+11)
x=8 x=-11
El numero = x
El cuadrado del numero = x²
3x + x² = 88
x² + 3x - 88 = 0 Factorizas trinomio de la forma x² + bx + c
(x + 11)(x - 8) = 0 Tiene como resultado dos raices reales
x + 11 = 0
x = - 11
o
x - 8 = 0
x = 8
Solucion.
( 8 , - 11)