Question

Efisiensi pada trafo 60%. Jika energi listrik yg dikeluarkan 300 Joule, brpakah energi listrik yg masuk trafo?

Answer 1

Diketahui:
η = 60%
Ws = 300 J

Ditanya: Wp  . . . ?

Penyelesaian : 
η = (Ws / Wp) x 100%
60% = (300 J / Wp) x 100%
6 = 3000 J / Wp
Wp = 3000 J / 6
Wp = 3000 J / 6
Wp = 500 J

Answer 2

60% = (300 J / Wp) x 100%
6 = 3000 J / Wp
Wp = 3000 J / 6
Wp = 3000 J / 6
Wp = 500 J