pole ma 36
Wiec :
1 bok(a) = 4
2 bok (b) =9
bo 9*4 =36
Wiec trzeba obliczyc to twierdzeniem pitagorasa
a^2+b^2=c^2
4^2+9^2=c^2
16+81 = c^2
91 = c^2
c=(pierwiastek z 91)
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pole ma 36
Wiec :
1 bok(a) = 4
2 bok (b) =9
bo 9*4 =36
Wiec trzeba obliczyc to twierdzeniem pitagorasa
a^2+b^2=c^2
4^2+9^2=c^2
16+81 = c^2
91 = c^2
c=(pierwiastek z 91)