Question

E)(2y - √3 )(y+1)
f)(a+√2)(a - √3)
g)(2√2 + k )(√2 - k )

Answer 1

E)(2y - √3 )(y+1)=2y²+2y-√3y-√3=2y²+y(2-√3)-√3
f)(a+√2)(a - √3)=a²-√3a+√2a-√6=a²-a(√3-√2)-√6
g)(2√2 + k )(√2 - k )=4-2√2k+√2k-k²=4-√2k-k²