(2·⁵/₆)²-(3²-√1⁷/₉)=
=100/36-(9-4/3)=
=100/36-7i2/3=
=25/9-7i6/9=
=2i7/9-7i6/9=
= -4i8/9
Oto rozwiazanie nie zapisywałam równania bo szkoda miejsca :
(2/1*5/6)x^{2}-(3x^{2}-\sqrt{x}17/9)=(5/9)x^{2}-(9-\sqrt{x}17/9)=
=25/9-(9-4/3)=25/9-4/3=25/9-12/9=13/9
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(2·⁵/₆)²-(3²-√1⁷/₉)=
=100/36-(9-4/3)=
=100/36-7i2/3=
=25/9-7i6/9=
=2i7/9-7i6/9=
= -4i8/9
Oto rozwiazanie nie zapisywałam równania bo szkoda miejsca :
(2/1*5/6)x^{2}-(3x^{2}-\sqrt{x}17/9)=(5/9)x^{2}-(9-\sqrt{x}17/9)=
=25/9-(9-4/3)=25/9-4/3=25/9-12/9=13/9