x - ilośc owiec I pasterza y - ilośc owiec II pasterza
x+y=585
4(x-23)=(y+23)
x=585-y
4(585-y-23)=y+23
2340-4y-92=y+23
-4y-y=23-2340+92
-5y=-2225
y=445
x=585-445
x=140
odp: Pierwszy pasterz miał 140 owiec , a drugi 445 owiec.
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x - ilośc owiec I pasterza
y - ilośc owiec II pasterza
x+y=585
4(x-23)=(y+23)
x=585-y
4(585-y-23)=y+23
2340-4y-92=y+23
-4y-y=23-2340+92
-5y=-2225
y=445
x=585-445
x=140
odp: Pierwszy pasterz miał 140 owiec , a drugi 445 owiec.