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Ob=3n-5+3n-4+3n-3=9n-12
zał. 3n-5≥1∧n∈N
3n≥6
n≥2 ∧ n∈N→n={2,3,4,5,...}
średni 3n-4
najdłuższy 3n-3
obwód= 3n-5+3n-4+3n-3=9n-12=3(3n-4)
IIbok----3n-5+1=3n-4
IIIbok----3n-4+1=3n-3
ob=3n-5+3n-4+3n-3=9n-12