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F1 = F2 = 10 N
Penyelesaian :
a. Mengapit sudut (α) = 30°
R = √(F1²+F2² + 2xF1xF2x cosα)
= √(10²+10² + 2x10x10x cos 30)
= √(100+100 + 2x100x1/2√3)
= √200 + 100√3)
= √200√3
= √373,2
= 19,31 N
b. Berimpit dan serah :
R = F1 + F2
= 10 + 10
= 20 N
C. Berlawanan arah :
R = F1 - F2
= 10 - 10
= 0 (konstan)