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√a²+b²+2ab cosβ = 2 √a²+b²-2ab cosβ
(√a²+b²+2ab cosβ)² = (2 √a²+b²-2ab cosβ)²
a²+b²+2ab cosβ = 4 (a²+b²-2ab cosβ)
a²+a²+2a.a cosβ = 4 (a²+a²-2a.a cosβ)
2a²+2a² cosβ = 4 (2a²-2a² cosβ)
2a²+2a² cosβ = 8a²-8a² cosβ
6a² = 10a² cosβ
cosβ = 6a²/10a² = 6/10 = 3/5 =0.6
β = 53