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= √ 12² + 5²
= √ 144 + 25
= √ 169
= 13cm
r = 2 CM
r = 3 CM
D = 12 cm
dit : P ?
MAKA :
P² = D² + (R+r)²
P² = 12² + (3+2)²
P² = 144 + 25
P = √169
P = 13 cm
jadi jarak titik pusat A dan B = 13 cm