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= 36
jawwaban soal A
n(a) = { (1,5) (5,1) (2,4) (4,2) (3,3) }
= 5
peluang
p(A) = 5/36
jawaban soal B
n(a) = { (2,2) (2,4) (2,6) ( 4,2) (4,4) (4,6) (6,2) (6,4) (6,6) }
= 9
peluang
p(A) = 9/36
= 1/4