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(√10-3x)(√10+3x)(10-9x²)=
(10-9x²)(10-9x²)=
100-90x²-90x²+81x⁴ =
81x⁴-180x²+100
(√10-3x)(10-9x²)(3x+√10)=(√10-3x)(√10+3x)(10-9x²)=
(10-9x²)(10-9x²)=100-180x²+81x⁴
ale jeśli w drugim nawiasie miało byc +(tak mi lepiej pasuje,), to mamy:
(10-9x²)(10+9x²)=100-81x⁴