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=[2(√3-1)]/[(√3-1)(√3+1)] - (√3-1)/[(√3+1)(√3-1)] + 5-√3/2=
=(2√3+2)/(3+√3-√3-1) - (√3-1)/(3-√3+√3-1) + 5-√3/2=
=2√3+2/2 - √3-1/2 + 5-√3/2=
=2√3+2-√3-1+5-√3=6