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b)(1-√3 )^3-(2-√2 )^3-2(1-√2)(1+√2)=1-√27-8-√8-2(1-√2)=1-3√3-8-2√2+2√2-2=-9-3√3
c)(2-2√3 )^2-(1-√3 )^3+(1-√3)(1+√3)=(4-8√3+12)-1+√27+1-√3=16-8√3+3√3-1√3=16-6√3
d)2(1-√5 )^3-(1+√3)(√3-1)=2-2√125-√3-1=2-10√5-√3-1=1-10√5-√3