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7(a-5)+2(3a-2)=
-3(x^2-x+1)-2-x^2+4)=
2x1x-5-3(x^2-2x)=
5a(a-1)+17a^2-10a=
-1(5a+3)+7(a-3)=
10x(2x-3)-6x(1-5x)=
-4(x-1)+8(x-2)=
12(x-2)-3(3x+1)=
-4x(x-1)-2x(3-x)=
4a(2-a)-3(7a-5)=
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