Dodałam załącznik . Proszę o chociaż część zadan . Daje naj .
3 .
a |2| <--- to znaczy pierwiastek = 8
a = 4 |2|
a< --- podstawa
r = 2|2|
P = 2Pi r 2 + 2 Pi r * H
P = 2 PI * (2|2|)2 + 2Pi * 2|2| * 4|2| =16 Pi + 32Pi = 48Pi
5.
Obw. =2Pir
9/2 Pi = 2 Pi r
r = 4,5
P = Pi r2
P= pi (4,5) 2
P= 20,25 Pi
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3 .
a |2| <--- to znaczy pierwiastek = 8
a = 4 |2|
a< --- podstawa
r = 2|2|
P = 2Pi r 2 + 2 Pi r * H
P = 2 PI * (2|2|)2 + 2Pi * 2|2| * 4|2| =16 Pi + 32Pi = 48Pi
5.
Obw. =2Pir
9/2 Pi = 2 Pi r
r = 4,5
P = Pi r2
P= pi (4,5) 2
P= 20,25 Pi