a)
(log0,08+3log0,5)^-3=(log0,08+log(0,5)^3)^-3=(log0,08+log0,125)^-3=log(0,8·0,125)^-3=
=(log(8/100·1/8)^-3=(log (1/100))^-3=(log10^-2))^-3=(-2log10)^-3=(-2·1)^-3=(-2)^-3=-1/8
b)
7^(2+log49 25)=7^2·7^log49 25=49·7log7^2 (5^2)=49·7^(1/2·2log7 7)=49·7^log7 7))=
49·7^1=49·7=343
c)
log3 0,375-log3 (1/8)=log3 (0,375:1/8)=log3(3/8·8)=log3 3=1
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a)
(log0,08+3log0,5)^-3=(log0,08+log(0,5)^3)^-3=(log0,08+log0,125)^-3=log(0,8·0,125)^-3=
=(log(8/100·1/8)^-3=(log (1/100))^-3=(log10^-2))^-3=(-2log10)^-3=(-2·1)^-3=(-2)^-3=-1/8
b)
7^(2+log49 25)=7^2·7^log49 25=49·7log7^2 (5^2)=49·7^(1/2·2log7 7)=49·7^log7 7))=
49·7^1=49·7=343
c)
log3 0,375-log3 (1/8)=log3 (0,375:1/8)=log3(3/8·8)=log3 3=1