September 2018 1 11 Report

\frac{(3^2)^4 * 49^6}{21^3 * 7^5} -do obliczenia, proszę aby podać wszystkie rozwiązania (wynik to 583443)

27^3 * \frac{1}{9^{2}} * \frac{1}{81} * (\frac{1}{3})^2

(2\frac{2}{5})^{-1} : (3\frac{1}{3})^{-2}

[0,2^{-1} + (-0,3)^{-1}]^{-2}


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