Do jutra błagam o pomoc jak to jest zrobione no nie umiem ;( zadanie w załączniku
1/x+x/x+2=1
1+2+1=x
4=x
(1/x)+(x/x+2)=1
(x+2)/(x^2+2x)+(x^2)/(x^2+2x)=1
(x^2+x+2)/(x^2+2x)=1 /×(x^2+2x)
x²+x+2=x²+2x /-x²
x+2=2x /-x
2=x
x=2
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1/x+x/x+2=1
1+2+1=x
4=x
(1/x)+(x/x+2)=1
(x+2)/(x^2+2x)+(x^2)/(x^2+2x)=1
(x^2+x+2)/(x^2+2x)=1 /×(x^2+2x)
x²+x+2=x²+2x /-x²
x+2=2x /-x
2=x
x=2