Question

Do 80g 15% roztworu H2SO4 dodano 20g wody. Jakie jest stężenie otrzymanego roztworu.HELP

Answer 1

C%=ms/mr*100%
15=ms/80*100
15=100ms/80 /*80
1200=100ms /:100
12=ms

c%=12/100 *100%
c%=1200/100
c%=12%

Answer 2

Cp=15%
mr=80g
mw=20g
cp1=?
-------------------------------------------------
cp=ms*100%/mr
ms=cp*mr/100%=15%*80g/100%=12g
mr1=mr+mw=80g+20g=100g
cp1=ms*100%/mr1
cp1=12g*100%/100g=12%