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mr1=50g
C%1=2%
ms=?
C%=(msx100%)/mr
2=100ms/50g
ms=1g
C%2=?
mr=50g+50gH2O=100g
ms=1g
C%=1gx100%/100g
C%=1%
Zad. 2
1kg=100dag=1000g
ms=479g
mr=1479g
C%=479gx100%/1479g
C%=32,39% - wynik podany w przybliżeniu.
2% w: 100g r-ru - 2g subst - 98g rozp
100g x
x=100*1/100
x=1g
ms=1g
mr-ru=50g+50g=100g
Cp=1g*100%/100g
Cp=1g
2)
ms=479g
mr-ru=1000g(1kg)+479g=1479g
Cp=ms*100%/mr-ru
Cp=479g*100%/1479g
Cp=32,38%
na 100g roztwory przypada 2 g substancji
czyli:
100gr ---> 2 g s
50gr ---> xgs
xgs= 50g * 2g /100g
xg=1g
masa roztworu=50 g , a po dodaniu wody = 100g
masa substancji=1g
Cp=ms/mr * 100%
Cp=1g/100g * 100%
cp=1%
2.
1 kg= 1000 gramów H2O
ms= 479g
mr= 1000g + 479g= 1479g
Cp=ms/mr*100%
Cp=479/1479*100%
Cp=32,38%