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y- masa roztworu
x/y * 100% = 30%
x=0.3y
stezenie po dolaniu 20kg wody
x/20+y * 100%= 20%
x/20+y=0.2 wstawiamy x=0.3y
0.3y/20+y=0.2
0.2(20+y)=0.3y
4+ 0.2y=0.3y
4=0.1y
y=40 ilosc wody na poczatku
40+20=60kg masa otrzymanego roztworu