Do 270 g 12% roztworu dosypano jeszcze 30 g tej soli. Oblicz stężenie procentowe powstałego roztworu.Prosze o pomoc :)
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mr=270g
ms=Cp*mr/100%
ms=12*270/100
ms = 32,4g
Dodano 30g soli, więc:
ms=32,4g+30g=62,4g
mr=270g+30g=300g
Cp=ms*100%/mr
Cp=62,4*100/300
Cp = 20,8%