Ile gramów azotanu(V) potasu pozostanie po odparowaniu wody z 750 cm³ roztworu tej soli, o stężeniu 0,3 mol/dm³?
V = 750cm³ = 0,75dm³ (1dm³ = 1000cm³)Cm = 0,3 mol/dm³Cm = n/V ⇔ n = Cm*Vn = 0,75dm³ * 0,3mol/dm³ = 0,225 mola KNO₃MKNO₃ = 101g/moln = m/M ⇔ m = n*Mm = 101*0,225 = 22,725g KNO₃
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V = 750cm³ = 0,75dm³ (1dm³ = 1000cm³)
Cm = 0,3 mol/dm³
Cm = n/V ⇔ n = Cm*V
n = 0,75dm³ * 0,3mol/dm³ = 0,225 mola KNO₃
MKNO₃ = 101g/mol
n = m/M ⇔ m = n*M
m = 101*0,225 = 22,725g KNO₃