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Cmol1= 0,5mol/dm3
+10g NaOH
Cmol2=?
n=Cmol*Vr
n=0,5mol/dm3*0,25dm3= 0,125 mola
ms= n*M
ms= 0,125 moli*40g/mol= 5g
ms= 5g + 10g= 15g
n=ms/M
n= 15g/40g/mol= 0,375 moli
Cmol= 0,375moli/0,25dm3= 1,5mol/dm3