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dane:
K= 4* 10 do -4
[H+]=0,1 mol/dm3
Szukane:
α=?
α=-K+√(K²-4CK)/2C
α=-4*10^-4+√[4*10^-4²*0,1*(-4*4*10^-4)]/2*0,1
α=0,06=6%