jaki to odczyn? [OH-]=0,0001 mol/dm3
[OH-]=10^-4
pOH=-log [OH-]
pOH=4
pH=14-pOH
pH=10
Odczym zasadowy
-log 0,0001 = 4 = pOH
pH + pOH = 14
pH = 14 - 4
pH = 10
Odczyn zasadowy
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[OH-]=10^-4
pOH=-log [OH-]
pOH=4
pH=14-pOH
pH=10
Odczym zasadowy
-log 0,0001 = 4 = pOH
pH + pOH = 14
pH = 14 - 4
pH = 10
Odczyn zasadowy