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2 C3H5(OH)3 + O2 ----> 6 C + 8 H2O
M 2 C3H5(OH)3 = 184g\mol
M O2 = 32g\mol
100g 2 C3H5(OH)3 ------- x g O2
184g 2 C3H5(OH)3 ------- 32g O2
x = około 17,39g
d = m\V
V = m\d
V = 17,39g \ 1,43g\dm3
V = około 12 dm3
Odp: Objętość tlenu wynosi około 12 dm3. ;)