NaOH cm=0,1 mol/dm3 V=? HCl V=20cm3 cm=0,12 mola/dm3 następuje miareczkowanie
NaOH + HCl ---> NaCl + H2O
0,1*x = 0,12*0,02
0,1*x = 0,0024
x = 0,024dm3
x = 24cm3 HCl
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NaOH + HCl ---> NaCl + H2O
0,1*x = 0,12*0,02
0,1*x = 0,0024
x = 0,024dm3
x = 24cm3 HCl