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Masa glicerolu=6*12u(C)+10*1u(H)+6*16u(O)+6*1u(H)=184u
Masa tlenu=2*16u=32u
z proporcji:
184g glicerolu- 32g tlenu
100 g glicerolu- xg tlenu
x=100g*32g/184g
x=17,39g tlenu
wzór na gęstość
d=m/V
V=m/d
V=17,39g/1,43g/dm3
V=12,161dm3=12161cm3